a) konvergerar, b) divergerar:\[\int_0^{\infty} e^{-x}\, dx=\lim_{N\to\infty}\int_0^N e^{-x}\, dx= \] \[ \lim_{N\to\infty}\Big[-e^{-x}\Big]_{0}^{N}= \lim_{N\to\infty}(-e^{-N}+e^0)=1. \] \[ \int_0^1 x^{-3/2}\, dx=\lim_{\epsilon\to 0+}\int_{\epsilon}^1 x^{-3/2}\, dx= \]\[\lim_{\epsilon\to 0+}\Big[-2x^{-1/2}\Big]_{\epsilon}^1= \lim_{\epsilon\to 0+}(-2+2\epsilon^{-1/2})=\infty. \]